# Difference between revisions of "AI:Regression Problems"

(→Linear regression with 1 variable (Univariate linear regression)) |
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==Linear regression with 1 variable (Univariate linear regression)== | ==Linear regression with 1 variable (Univariate linear regression)== | ||

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+ | There is some [[linear algebra]] involved. | ||

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;h(x) = θ<sub>(0)</sub> + θ<sub>(1)</sub>*x | ;h(x) = θ<sub>(0)</sub> + θ<sub>(1)</sub>*x | ||

:θ are the hypothesis parameters, it is the weight a feature gets. For the multiplication tables θ is just the table you are working on. So for the table of 4, in the above formula θ(1) = 4 | :θ are the hypothesis parameters, it is the weight a feature gets. For the multiplication tables θ is just the table you are working on. So for the table of 4, in the above formula θ(1) = 4 |

## Latest revision as of 15:34, 26 May 2019

Learning from a training set.
A training set has m samples of x's (input variables or features) and the resulting y's (output/target variables)

For regression problems the learning algorithm needs to find the best matching hypothesis to map the input to the output values.

The hypothesis (h) can be:

## Linear regression with 1 variable (Univariate linear regression)

There is some linear algebra involved.

- h(x) = θ
_{(0)}+ θ_{(1)}*x - θ are the hypothesis parameters, it is the weight a feature gets. For the multiplication tables θ is just the table you are working on. So for the table of 4, in the above formula θ(1) = 4

The aim of the learning algorithm is to choose θ(0) and θ(1) so that the result for all input values is as close as possible to the given output values. The mean difference is calculated by a 'Squared error cost function' like:

This means that for each sample in the dataset we calculate the square value of the difference between the output of our hypothesis(h) and the actual value in the training set(y). We sum it all up and multiply by half the number of rows in the dataset.

- m is the number of samples in the data set.
- The square of the difference is taken to force a positive number.

We need to pick θ_{(0)} and θ_{(1)} so that the outcome of the cost function is as close as possible to 0