Difference between revisions of "Iloc"

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<code>df2.groupby('ID').apply(lambda d: d.iloc[-1])</code>
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<code>df.groupby('ID').apply(lambda d: d.iloc[-1])</code>

Revision as of 14:18, 30 December 2019

Function for a Pandas#DataFrame locating an index(row)

Find the latest value per ID for a dataframe like this
Index ID date value
0 1 2019-06-14 23:00:03 7550.00
0 2 2019-06-15 00:00:03 7690.00
23560 17 2019-12-15 18:10:43 25.50
23561 17 2019-12-16 18:10:45 25.52

df.groupby('ID').apply(lambda d: d.iloc[-1])